Published by:
CGP EDU Academic Team
Published on: August 21, 2026
A uniform rod of length 200 cm and mass 500 g is balanced on a wedge placed at 40 cm mark. A mass of 2 kg is suspended from the rod at 20 cm and another unknown mass 'm' is suspended from the rod at 160 cm mark as shown in the figure. Find the value of 'm' such that the rod is in equilibrium, (g = 10 m/s 2 )
A
kg
B
kg
C
kg
D
kg
Text Solution
Verified by ExpertsThe correct answer is:
From principle of moments
2x20 = 0.5x60 + mx120
2 = 1.5 +6m
0.5 = 6m
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
PHYSICS
Section A
The escape velocity from the Earth's Surface is v. The escape velocity from the s…
A cup of coffee cools from 90°C to 80°C in t minutes, when the room temperature is 20°C. The time t…
A thick current carrying cable of radius 'R r carries current T uniformly distributed across its cr…
Polar molecules are the molecules:
Find the value of the angle of emergence from the prism. Refractive index of the glass is .
A parallel plate capacitor has a uniform electric field 'E' in the space between the plates, If the…